How to use

Disjoint

in

org.deegree.filter.spatial

  break;
case DISJOINT:
  propertyName = ( (Disjoint) operator ).getPropName();
  geometry = ( (Disjoint) operator ).getGeometry();
  break;
case DWITHIN:

@Override
public <T> boolean evaluate( T obj, XPathEvaluator<T> xpathEvaluator )
            throws FilterEvaluationException {
  for ( TypedObjectNode paramValue : propName.evaluate( obj, xpathEvaluator ) ) {
    Geometry geom = checkGeometryOrNull( paramValue );
    if ( geom != null ) {
      Geometry transformedLiteral = getCompatibleGeometry( geom, geometry );
      return geom.isDisjoint( transformedLiteral );
    }
  }
  return false;
}

case DISJOINT:
  Disjoint disjoint = (Disjoint) op;
  return new Disjoint( copy( disjoint.getPropName() ), disjoint.getGeometry() );
case DWITHIN:
  DWithin dwithin = (DWithin) op;

  break;
case DISJOINT:
  geometry = ( (Disjoint) operator ).getGeometry();
  break;
case DWITHIN:

spatialOperator = new Disjoint( param1, param2 );
break;

Disjoint disjoint = (Disjoint) op;
builder.add( propNameExpr ).add( ".STDisjoint(" );
builder.add( toProtoSQL( disjoint.getGeometry(), storageCRS, srid ) );
builder.add( ")=1" );
break;

  return new Crosses( (Expression) os[0], (Geometry) os[1] );
case DISJOINT:
  return new Disjoint( (Expression) os[0], (Geometry) os[1] );
case DWITHIN:
  DWithin d = (DWithin) o;

builder.add( toProtoSQL( disjoint.getGeometry(), storageCRS, srid ) );
builder.add( ")" );
break;

spatialOperator = new Disjoint( param1, param2 );
break;

spatialOperator = new Disjoint( param1, param2 );
break;