How to use

sortBy

function

in

CollectionChain

_.chain(db)
  .filter(a => _.includes(_.lowerCase(a.name), _.lowerCase(criteria.name)))
  .filter(a => a.age > criteria.age.min && a.age < criteria.age.max)
  .filter(a => a.yearsActive > criteria.yearsActive.min && a.yearsActive < criteria.yearsActive.max)
  .sortBy(a => a[sortProperty])
  .value()

/**
 * Parse & merge multiple rank results from redis.
 * @param  {array}  ranks In this format: [['foo', '39', 'bar', '13'], ['foo', '11']]
 * @return {object}       In this format: [{ foo: 50 }, { bar: 13 }]
 */
const createRankTotalParser = (direction, startingAt, limit) => ranks => {
 return _.chain(ranks)
  .flatten()
  .chunk(2)
  .reduce((acc, [key, count]) => _.tap(acc, acc => {
   acc[key] = (acc[key] || 0) + Number(count);
  }), { })
  .toPairs()
  .sortBy(([, count]) => direction === 'asc' ? count : -count)
  .drop(startingAt)
  .takeWhile((value, index) => limit <= 0 || index < limit)
  .map(([key, count]) => ({ [key]: count }))
  .value();
}

 .groupBy(getHighlight)
 .toPairs()
 .sortBy(0)
 .value();
const data = [];
  .sortBy((f) => parseJobFromURL(f.upstream).jobid)
  .map((item) => ({ source: item.source, upstream: item.upstream }))
  .value();
for (const type of Object.keys(groupedByType)) {
 groupedByType[type] =
  _.sortBy(groupedByType[type], r => 0 - (r.prs.length));

  return { name, mean };
 })
 .sortBy('mean')
 .value();
resolve(result);

  });
newsList = _.chain(newsList).values(newsList).sortBy(function (news) {
  return -news._at;
}).value();