How to use

withId

method

in

net.nemerosa.ontrack.model.structure.Branch

  public Branch update(NameDescriptionState form) {
    return of(project, form).withId(id).withDisabled(form.isDisabled());
  }
}

protected Branch toBranch(ResultSet rs, Function<ID, Project> projectSupplier) throws SQLException {
  ID projectId = id(rs, "projectId");
  ID branchId = id(rs);
  return Branch.of(
      projectSupplier.apply(projectId),
      new NameDescription(
          rs.getString("name"),
          rs.getString("description")
      )
  )
      .withId(branchId)
      .withSignature(readSignature(rs))
      .withType(getBranchType(branchId))
      .withDisabled(rs.getBoolean("disabled"));
}

@Override
public Branch newBranch(Branch branch) {
  // Creation
  try {
    int id = dbCreate(
        "INSERT INTO BRANCHES(PROJECTID, NAME, DESCRIPTION, DISABLED, CREATION, CREATOR) VALUES (:projectId, :name, :description, :disabled, :creation, :creator)",
        params("name", branch.getName())
            .addValue("description", branch.getDescription())
            .addValue("disabled", branch.isDisabled())
            .addValue("projectId", branch.getProject().id())
            .addValue("creation", dateTimeForDB(branch.getSignature().getTime()))
            .addValue("creator", branch.getSignature().getUser().getName())
    );
    // Returns with ID
    return branch.withId(id(id));
  } catch (DuplicateKeyException ex) {
    throw new BranchNameAlreadyDefinedException(branch.getName());
  }
}