How to use

distinctWithQuery

method

in

io.vertx.ext.mongo.MongoService

public io.vertx.rxjava.ext.mongo.MongoService distinctWithQuery(String collection, String fieldName, String resultClassname, JsonObject query, Handler<AsyncResult<JsonArray>> resultHandler) { 
 delegate.distinctWithQuery(collection, fieldName, resultClassname, query, resultHandler);
 return this;
}

 public static io.vertx.ext.mongo.MongoService distinctWithQuery(io.vertx.ext.mongo.MongoService j_receiver, java.lang.String collection, java.lang.String fieldName, java.lang.String resultClassname, java.util.Map<String, Object> query, io.vertx.core.Handler<io.vertx.core.AsyncResult<java.util.List<Object>>> resultHandler) {
  io.vertx.core.impl.ConversionHelper.fromObject(j_receiver.distinctWithQuery(collection,
   fieldName,
   resultClassname,
   query != null ? io.vertx.core.impl.ConversionHelper.toJsonObject(query) : null,
   resultHandler != null ? new io.vertx.core.Handler<io.vertx.core.AsyncResult<io.vertx.core.json.JsonArray>>() {
   public void handle(io.vertx.core.AsyncResult<io.vertx.core.json.JsonArray> ar) {
    resultHandler.handle(ar.map(event -> io.vertx.core.impl.ConversionHelper.fromJsonArray(event)));
   }
  } : null));
  return j_receiver;
 }
}