How to use

distinct

method

in

io.vertx.ext.mongo.MongoService

public io.vertx.rxjava.ext.mongo.MongoService distinct(String collection, String fieldName, String resultClassname, Handler<AsyncResult<JsonArray>> resultHandler) { 
 delegate.distinct(collection, fieldName, resultClassname, resultHandler);
 return this;
}

public static io.vertx.ext.mongo.MongoService distinct(io.vertx.ext.mongo.MongoService j_receiver, java.lang.String collection, java.lang.String fieldName, java.lang.String resultClassname, io.vertx.core.Handler<io.vertx.core.AsyncResult<java.util.List<Object>>> resultHandler) {
 io.vertx.core.impl.ConversionHelper.fromObject(j_receiver.distinct(collection,
  fieldName,
  resultClassname,
  resultHandler != null ? new io.vertx.core.Handler<io.vertx.core.AsyncResult<io.vertx.core.json.JsonArray>>() {
  public void handle(io.vertx.core.AsyncResult<io.vertx.core.json.JsonArray> ar) {
   resultHandler.handle(ar.map(event -> io.vertx.core.impl.ConversionHelper.fromJsonArray(event)));
  }
 } : null));
 return j_receiver;
}
public static io.vertx.ext.mongo.MongoService distinctWithQuery(io.vertx.ext.mongo.MongoService j_receiver, java.lang.String collection, java.lang.String fieldName, java.lang.String resultClassname, java.util.Map<String, Object> query, io.vertx.core.Handler<io.vertx.core.AsyncResult<java.util.List<Object>>> resultHandler) {